angell1 angell1
  • 17-03-2016
  • Mathematics
contestada

the length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle

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zerofrancisco zerofrancisco
  • 17-03-2016
the perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
p = 2l + 2w
2w = p - 2l
w = (p - 2l)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
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