Question

Choose the product. a 2b 3 · 6ab 2

Answer 1

Let's reorganize the problem to make it easier to understand... we can change the order because of the commutative property of multiplication.

(3)2ab * (2)6ab=
6ab * 12ab=
72 a^2b^2

Answer 2

Answer:

$6(a^{3})(b^{5})$

Step-by-step explanation:

we have

$a^{2}b^{3}6ab^{2}$

Group terms that contain  the same variable

$6(a^{2}a)(b^{3}b^{2})$

sum the power

$6(a^{2+1})(b^{3+2})$

$6(a^{3})(b^{5})$