Question

in a calorimeter, 20 g of ice absorbs heat with an enthalpy of fusion of 334 j/g. what is the heat absorbed

Answer 1

Answer:The heat absorbed by the 20 g of ice is 6,680 Joules.

Explanation:

Enthalpy of fusion is defined as amount of heat required to change the 1 mole of substance from solid phase to liquid phase  when pressure and temperature remains constant.

Here in the question we are given with an enthalpy of fusion of 334 J/g. Which means that 334 Joules of heat will be required to melt 1 gram of ice.

Mass of ice in calorimeter = 20 g

Heat absorbed by the 20 g of ice =$20 g\times 334 J\g=6,680 J$

Answer 2

The amount of heat energy absorbed by the 20 g of ice in the calorimeter is 6680 J

Data obtained from the question

From the question given above, the following data were obtained:

• Mass of ice = 20 g
• Heat of fusion (ΔHf) = 334 J/g

• Heat (Q) =?

How to determine the heat absorbed

The heat absorbed can be obtained as illustrated below:

Q = m × ΔHf

Q = 20 × 334

Q = 6680 J

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