Respuesta :
Since his line of sight 63 degrees makes with the tip of the building
Tan63° = height of building / Horizontal distance
tan63° = Height / 50
50tan63° = Height
Height = 50tan63°
Height ≈ 50*1.9626
Height ≈ 98.13 m
Height of the building is ≈ 98.13 m. Mind you in solving for this height we have neglected the height of Daniel.
The height of building actually should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.
Tan63° = height of building / Horizontal distance
tan63° = Height / 50
50tan63° = Height
Height = 50tan63°
Height ≈ 50*1.9626
Height ≈ 98.13 m
Height of the building is ≈ 98.13 m. Mind you in solving for this height we have neglected the height of Daniel.
The height of building actually should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.