Question

How much heat is absorbed if 45 grams of sweat is evaporated from someone's skin? dhvap for water at body temperature is 2.41 kj/g?

Answer 1

Answer : 108 kJ of heat is absorbed

Explanation :

Enthalpy of vaporization of water at body temperature is 2.41 kJ/g

That means we need 2.41 kJ to evaporate 1 gram of sweat.

Let us use this as a conversion factor to find the amount of heat needed to evaporate 45 grams of sweat.

The equation can be set as follows.

$45gSweat \times \frac{2.41 kJ}{g} = 108 kJ$

Therefore we can say that 108 kJ of heat is absorbed when sweat is evaporated from someone's skin.