Question

When ammonium nitrate (nh4no3) explodes, the products are nitrogen, oxygen and water. when 40 grams of ammonium nitrate explode, 14 grams of nitrogen and 8 grams of oxygen form. how many grams of water form?

Answer 1

Answer:

              18 g of H₂O

Solution:

The Balance Chemical Reaction is as follow,

                              2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation ,

              160 g (2 mole) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                       40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                      X =  (40 g × 72 g) ÷ 160 g

                      X  =  18 g of H₂O

Answer 2

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

Let's consider the balanced equation for the decomposition reaction of ammonium nitrate.

2 NH₄NO₃ → 2 N₂ + O₂ + 4 H₂O

According to Lavoisier's law of conservation of mass, the sum of the masses of the reactants must be equal to the sum of the masses of the products over a chemical reaction. The mass of water formed is:

$mNH_4NO_3 = mN_2 + mO_2 + mH_2O\\mH_2O = mNH_4NO_3 - mN_2 - mO_2\\mH_2O = 40 g - 14 g - 8 g = 18 g$

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

You can learn more about Lavoisier's law here: https://brainly.com/question/11429078