Question

Vinegar contains 5.00% acetic acid by mass and has a density of 1.01g/ml. what mass (in grams) of acetic acid is present in 5.00 l of vinegar

Answer 1

Mass % of acetic acid in vinegar = 5.00 %

That means 5.00 g acetic acid is present per 100 g Vinegar

Given the density of vinegar solution = 1.01 g/mL

Converting the mass of vinegar to volume:

$100 g vinegar *\frac{1mL}{1.01 g} *\frac{1L}{1000mL}=0.099 L$

5.00 g acetic acid is present in 0.099L vinegar solution.

Calculating the mass of acetic acid in 5.00 L vinegar solution:

$5.00 L vinegar solution * \frac{5.00 g acetic acid}{0.099 L vinegar solution} =253 g acetic acid$