Question

A 0.22-caliber handgun fires a 29-g bullet at a velocity of 770. m/s. calculate the de broglie wavelength of the bullet.

Answer 1

solution:

$\lambda =\frac{h}{mv}\\ h is planck's constant=6.626\times10^-34j.sec\\ m=mass=29g\\ =28\times10^-3kg\\ v=770m/sec\\ \lambda=\frac{6.626\times10^-34j.sec}{29\times10^-3\times770}$