Question

How much heat is absorbed by a 72g iron skillet when its temperature rises from 6oC to 27oC?

Answer 1

we will be using formula of heat absorbed

$Q=mc \Delta T$

where

Q is heat absorbed

m is mass

c is specific heat of iron skillet

$ \Delta T$ is temperature change

we are given

$m=72g$

$c=0.449J/g$

$\Delta T=27-6$

$\Delta T=21$

now, we can plug values

$Q=72*0.449*21$

$Q=678.888J$

so,

heat absorbed is 678.888J............Answer