Question

Han has to take statistics, economics, history, and composition next term in order to graduate. He takes each of these courses Monday through Thursday, one course per day, and can choose which days to take each course. How many different ways can Han make his schedule for next term?


PLzzzz help!

Answer 1

Since we are trying to arrange the classes in a sequence where none repeat, we are going to use a factorial, represented by $n!$, where $n$ is the number of items in the sequence.

Since we have four items in our sequence (four classes), our answer is going to be equal to $4!$, which is equal to 24, as shown below:

$4! = 4 \cdot 3 \cdot 2 \cdot 1 = 24$

There are 24 different ways.