Question

an old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 n/m what is the force applied to the scale by the car?

Answer 1

F = Ke
So… 39200 x (25/100) = 39200 x 0.25
F= 9800N

Answer 2

Answer:

Force applied to the scale by the car is 9800 N.

Explanation:

It is given that,

A spring scale is compresses by an old truck such that, x = 25 cm = 0.25 m

The spring constant for the industrial scale at the junkyard is, k = 39200 N/m

We need to find the force applied to the scale by the car. It can be calculated using the following relation as per Hooke's law :

F = -k x

negative sign shows the direction of force

$F=39200\ N/m\times 0.25\ m$

F = 9800 N

So, the force applied to the scale by the car is 9800 n. hence, this is the required solution.