Respuesta :
let us say hmm
p = months in Portugal
b = months in Brazil
Wolfrich learned 130 words in portugal, every month, so if he lived there 1 month, he got 130*p or 130*1 or 130 words only
two months, 130*2 or 260 words
three months 130*3 or 390 words and so on
so... if he lived only "p" months, he learned then, 130 * p, or 130p
in Brazil, he learned 150 monthly, same as before, if he lived "b" months, then he learned 150 * b, or 150b
he spent a total of 14 months on both places
so.. .whatever "b" is, and whatever "p" is, we know that
b + p = 14
and he learned a total of 1920 words
so... whatever 150b is, and whatever 130p is, we know that
150b + 130p = 1920
therefore
[tex] \bf \begin{cases} b+p=14\implies \boxed{p}=14-b\\ 150b+130p=1920\\[-0.5em] \hrulefill\\ 150b+130\left( \boxed{14-b} \right)=1920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 150b+1820-130b=1920\implies 20b=100\implies b=\cfrac{100}{20}\implies \blacktriangleright b=5 \blacktriangleleft \\\\\\ p=14-b\implies \blacktriangleright p=9 \blacktriangleleft [/tex]
Answer: P= 9 months
B=5 months
Step-by-step explanation: