Question

What are the magnitude (size) and direction of the cumulative force acting on the car shown in the picture A. 30 N to the right B. 2500 N down C. 30 N to the left D. 3500 N up

Answer 1

Answer: The correct answer is option(A).

Explanation:

Total forces exerting on the car = F

$F_r=50 N$= Force on car exerting in right direction

$F_l=20 N$= Force on car exerting in left direction

$F_u=2500 N$= Force on car exerting in upward direction

$F_d=2500 N$= Force on car exerting in downward direction

$F=F_r+F_l+F_u+F_d$

$(-F_u)=F_d$ (negative sign shows the direction)

Since, upward force are equal in magnitude but opposite in direction by which they will balance out each other.so, the net force car will be due to two forces $F_r$ and $F_l$

$F=F_r+F_l=50 N+(-20 N)=30 N$(negative shows the direction)

The magnitude (size) and direction of the cumulative force acting on the car will 30 N towards right direction.Hence, correct answer is option(A).

Answer 2

Answer:30n to the right

Explanation: