If a ball is thrown upward at 64 feet per second from the top of a building that is 120 feet high, the height of the ball is given by s = 120 + 64t − 16t2 feet where t is the number of seconds after the ball is thrown. how long after it is thrown is the height 120 feet?

Respuesta :

Graphing it you can find that the ball will be at 120ft at 4secs.
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