10.4 N
Given
m = 1.10 kg
θ = 15.0°
g = 9.81 m/s2
Solution
Fnet, y = ΣF y = Fn − Fg, y = 0
Fn = Fg, y = Fg
cosθ = mgcosθ
Fn = (1.10 kg)(9.81 m/s2
)(cos15.0°) = 10.4 N
Given values:
As we know the formula,
→ [tex]N' = mg Cos \Theta[/tex]
By substituting the values, we get
[tex]= 1.10\times 9.81\times Cos15^{\circ}[/tex]
[tex]= 10.42 \ N[/tex]
Thus the above approach i.e., "option c" is right.
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