Question

HURRY PLEASE WORTH 99pts

Read the two situations below. Determine which situation is a permutation and which is a combination. Explain in complete sentences how you made your conclusion and why.

Situation #1: From a group of 8 people, 5 will each win $1,000. How many different winning groups are possible? Situation

#2: Thirty people purchase lottery tickets. Three winning tickets will be selected at random. If first prize is $100, second prize is $50, and third prize is $10, in how many different ways can the prizes be awarded?

Complete your work in the space provided or upload a file that can display math symbols if your work requires it. Include your conclusions and calculations in your answer.

Answer 1

Situation #1: From a group of 8 people, 5 will each win $1,000. How many different winning groups are possible? Combination

There are different ways of combining and choosing the 5 people from the 8

#2: Thirty people purchase lottery tickets. Three winning tickets will be selected at random. If first prize is $100, second prize is $50, and third prize is $10, in how many different ways can the prizes be awarded? Situation = = Permutation

Permutation is getting a set of number or things that have different possible situations and reordering them

hope this helps

Answer 2

details like order make a difference in permutation while the same details do not matter in combination.

1. the 5 winners get the same prize so there is no difference. It is combination.

2. the prizes are different between 1, 2 and 3. so it is permutation.