Electric field due to a point charge is given by formula
[tex]E = \frac{kq}{r^2 + \frac{d^2}{4}}[/tex]
now due to negative charge also the magnitude of electric field will be same
only difference is the direction of field due to negative charge is radially inwards
now we can say that net field due to these two charges is given as
[tex]E = 2E_0cos\theta[/tex]
[tex]E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}[/tex]
[tex]E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}[/tex]
now it is given that distance r is very large than "d" so we can say
[tex]E = \frac{kqd}{r^3}[/tex]
so above is the electric field due to dipole