Question

How would I solve this

Answer 1

Note that this is a 30-60-90 triangle, in which  8 is in the one's place, and y is in the √3 place (1, √3 , 2)

Multiply

8 x √3 = 8√3 = 13.85, or 13.9 (rounded)

B) 13.9 is your answer

hope this helps

Answer 2

$tangent=\dfrac{opposite}{adjacent}\\\\\tan60^o=\dfrac{y}{8}\ \ \ |\tan60^o=\sqrt3\\\\\dfrac{y}{8}=\sqrt3\ \ \ \ |\cdot8\\\\\boxed{y=8\sqrt3}\to\boxed{y\approx13.9}$

Other method.

Two such triangles form an equilateral triangle (look at the picture).

The formula of a height of an equilateral triangle:

$h=\dfrac{a\sqrt3}{2}$

We have

$a=2\cdot8=16;\ h=y$

Substitute:

$y=\dfrac{16\sqrt3}{2}=8\sqrt3\approx13.9$