Question

f(x) = Square root of quantity x plus nine.; g(x) = 8x - 13
Find f(g(x)).
f(g(x)) = 2Square root of quantity two x minus one.
f(g(x)) = 8Square root of quantity x minus four.
f(g(x)) = 2Square root of quantity two x plus one.
f(g(x)) = 8Square root of quantity x plus nine. - 13

Answer 1

f(x) = sqrt(x) + 9
g(x) = 8x - 13

f(g(x)) = f(8x - 3) = sqrt(8x - 13) + 9

Answer 2

Answer:

$2\sqrt{2x-1}$

Step-by-step explanation:

f(x) = Square root of quantity x plus nine.

Mathematically we can write this as:

$f(x)=\sqrt{x+9}$

$g(x)=8x-13$

We have to find $f(g(x))$

So, we have to replace x in f(x) with : 8x-13.

$f(g(x))=f(8x-13)$

= $\sqrt{8x-13+9}$

= $\sqrt{8x-4}$

= $\sqrt{4(2x-1)}$

= $2\sqrt{2x-1}$

Hence, answer is : f(g(x)) = 2 Square root of quantity two x minus one.