Question

A horse race has 13 entries and one person owns 5 of those horses. assuming that there are no​ ties, what is the probability that those five horses finish first, second, third, fourth, and fifth ​(regardless of​ order)? the probability first, second, third, fourth, and fifth is nothing.

Answer 1

There are 13 entries in total  

The owner has 5 horses.

If each horses has  the same  probability of winning, then the probability that the owners

Horses will come in first, second, third, and fourth will be as follows:

It was only specified that one of these horses needed to be in each position  

This makes it is a combination type problem because order does not matter  

We 5 horses

The probability that one of those 5 horses will be first is 5/13

The probability that one of those remaining  4 horses will be second is 4/12

The probability that one of those remaining  3 horses will be third is 3/11

The probability that one of those remaining 2 horses will be fourth is 2/10

The probability that one of those remaining 1 horses will be fifth is 5/9    

The total probability is that 0.00389