Question

If P = 4x4 - 3x3 + x2 - 5x + 11 and Q = -3x4 + 6x3 - 8x2 + 4x - 3 what is 2P + Q?

Answer 1

The given vaues of P and Q are

$P = 4x^4 -3x^3+x^2 -5x +11$

$Q = -3x^4 + 6x^3-8x^2+4x-3$

And we have to find the value of

$2P +Q$

For that, we have to multiply P by 2 and add the result to Q. That is

$2P+ Q = 2(4x^4-3x^3+x^2-5x+11)-3x^4+6x^3-8x^2 +4x-3$

$= 8x^4 -6x^3 +2x^2 -10x +22-3x^4 +6x^3 -8x^2 +4x-3$

$= 5x^4-6x^2-6x+19$

And that's the required result of 2P + Q .