Answer
Given data
Conc. of standard ddt = 6.44mg/l
Conc. of Internal standard chloroform = 1.41mg/l
Peak of standard ddt = 3979
Peak of internal standard chloroform = 9257
Required
Response factor (RF) = ?
Solution
As we know that
Response factor (RF) = Peak area/sample amount
So RF for standard ddt
RF = 3979/6.44 = 617.85 (answer)
RF for internal standard chloroform
RF = 9257/ 1.41= 6565.24 (answer)