Question

Write a balanced equation to show the reaction of sulfurous acid with lithium hydroxide to form water and lithium sulfite. write a balanced equation to show the reaction of sulfurous acid with lithium hydroxide to form water and lithium sulfite. h2s (aq) + 2 lioh (aq) → 2 h2o (l) + li2s (aq) hso3 (aq) + lioh (aq) → h2o (l) + liso3 (aq) h2so4 (aq) + lioh (aq) → h2o (l) + li2so4 (aq) hso4 (aq) + lioh (aq) → h2o (l) + liso4 (aq) h2so3 (aq) + 2 lioh (aq) → 2 h2o (l) + li2so3 (aq)

Answer 1

H_2SO_3(aq) + 2LiOH(aq) → Li_2SO_3(aq) + 2H_2O(ℓ)

Step 1. Write the unbalanced equation

H_2SO_3(aq) + LiOH(aq) → Li_2SO_3(aq) + H_2O(ℓ)

Step 2. Balance the equation

H_2SO_3(aq) + 2LiOH(aq) → Li_2SO_3(aq) + 2H_2O(ℓ)

Answer 2

Answer:

$2LiOH+H_{2}SO_{3}--->Li_{2}SO{3}+2H_{2}O$

Explanation:

The formula of lithium hydroxide is :LiOH

The formula of sulfurous acid is: H₂SO₃

the formula of lithium sulfite is : Li₂SO₃

The reaction will be:

$LiOH+H_{2}SO_{3}--->Li_{2}SO{3}$

Let us balance the equation

In order to balance Lithium will put two against LiOH.

$2LiOH+H_{2}SO_{3}--->Li_{2}SO{3}$

Sulfur is already balanced.

To balance oxygen we will add water to deficient side.

$2LiOH+H_{2}SO_{3}--->Li_{2}SO{3}+2H_{2}O$

This is balanced equation.