It is given in the question that QS bisects angle PQR .
[tex]m \angle PQS = 3x , m \angle RQS =2x+6[/tex]
And since, QS bisects angle PQR, therefore
[tex][tex]m \angle PQS = m \angle RQS[/tex][/tex]
Substituting the values of angle PQS and angle RQS, we will get
[tex]3x = 2x+6
\\
3x-2x=6
\\
x = 6[/tex]
PQR is twice of angle PQS. Therefore angle PQR is
[tex]m \angle PQR = 2*3*6 = 36 degree[/tex]
