Question

You are fixing the roof of your house when a hammer breaks loose and slides down. the roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 5.5 m/s when it reaches the edge. assume that the hammer is moving from the top of the roof to its right edge. part a what is the horizontal component of the hammer's velocity just as it leaves the roof?

Answer 1

The horizontal component of the hammer's velocity is 3.9 m/s.

The hammer falls with a velocity v along the roof which is at an angle θ with horizontal.

Resolve the velocity v into two components- horizontal component vcosθ and the vertical component v sinθ.

Calculate the horizontal component of the hammer's velocity, by substituting 5.5 m/s for v and 45° for θ.

$vcos\theta = (5.5 m/s)(cos45^o)=3.889 m/s$

The horizontal component of the hammer's velocity is 3.9 m/s