[tex]a)\\\dfrac{17+5n}{4}=\dfrac{17}{4}+\dfrac{5}{4}n\\\\b)\\\dfrac{8-9x}{3}=\dfrac{8}{3}-\dfrac{9}{3}x=\dfrac{8}{3}-3x\\\\c)\\\dfrac{4y-12}{2}=\dfrac{4}{2}y-\dfrac{12}{2}=2y-6\\\\d)\\\dfrac{25-8t}{5}=\dfrac{25}{5}-\dfrac{8}{5}t=5-\dfrac{8}{5}t\\\\e)\\\dfrac{18x+51}{17}=\dfrac{18}{17}x+\dfrac{51}{17}=\dfrac{18}{17}x+3[/tex]
