It is given in the question that,
Hawthorne Lane bisects the angle formed by Melville Road and Emerson Avenue. And the angle formed by Melville Road and Emerson Avenue is 119°.
Therefore angle formed by Melville Road anf Hawthorne Lane equals to angle formed by Hawthorne Lane and Emerson Avenue equals to
half of 119 = 59.5 degree.
And Dickinson Drive bisects the angle formed by Emerson Avenue and Thoreau Street. The measure of the angle formed by Emerson Avenue and Thoreau Street is 134°.
Therefore angle formed by Emerson Avenue and Dickinson drive equals to angle formed by Dickinson drive and Threau Street equals to half of 134 that is 67 each .
Hence the angle formed by Hawthrone Lane and Dickinson Drive is the sum of 59.5 and 67.That is
[tex]59.5 + 67 = 126.5 degree[/tex]