Respuesta :
Follow these steps:
- First, have the equation set up in your preference (I prefer -20 = 2x)
- Then, get the variable (x) by itself by divide both sides by 2
- Once you do that, you'll be left with this: -10 = x
Hope this helps!
If a > 0, then a ˣ > 0 for all real number
[tex]a^x > 0,\ a > 0\ \wedge\ x\in\mathbb{R}[/tex]
Therefore 2ˣ = -20 has not solution (x ∈ ∅).
If in the question is positive 20, then:
[tex] 2^x=20\ \ \ \ \ |\log_2\\\\\log_22^x=\log_220\\\\x\log_22=\log_2(4\cdot5)\\\\x=\log_24+\log_25\\\\x=\log_2^2+\log_25\\\\x=2\log_22+\log_25\\\\\boxed{x=2+\log_25} [/tex]
Used:
[tex]\log_ab^n=n\log_ab\\\\\log_aa=1\\\\\log_a(b\cdot c)=\log_ab+\log_ac[/tex]