Question

A new community sports complex is being built in Madison. The perimeter of the rectangular playing field is is 462 yards. The length of the field is 5 yards less than triple the width. What are the dimensions of the playing field?

Answer 1

we are given

The perimeter of the rectangular playing field is is 462 yards

Let's assume width=x

W=x

The length of the field is 5 yards less than triple the width

$L=3x-5$

we know that perimeter of rectangle is

$P=2L +2W$

now, we can plug values

$P=2(3x-5) +2x$

now, we can plug P=462

$462=2(3x-5) +2x$

now, we can solve for x

$8x-10=462$

$x=59$

so,

width =59

now, we can find length

$L=3*59-5$

$L=172$

so, dimensions are

length=172 yards and width=59 yards.........Answer