Question

How many atoms of oxygen are contained in 160 grams of N2O3?

Answer 1

above 80 grams 6 grams

Answer 2

Answer : The number of oxygen atoms are, $37.94\times 10^{23}$

Explanation : Given,

Mass of $N_2O_3$ = 160 g

Molar mass of $N_2O_3$ = 76.01 g/mole

First we have to calculate the moles of $N_2O_3$

$\text{Moles of }N_2O_3=\frac{\text{Mass of }N_2O_3}{\text{Molar mass of }N_2O_3}=\frac{160g}{76.01g/mole}=2.1mole$

As we know that $N_2O_3$ contains 2 number of nitrogen atoms and 3 number of oxygen atoms.

Now we have to calculate the number of atoms of oxygen.

As, 1 mole of $N_2O_3$ contains $3\times 6.022\times 10^{23}$ number of oxygen atoms

As, 2.1 mole of $N_2O_3$ contains $2.1\times 3\times 6.022\times 10^{23}=37.94\times 10^{23}$ number of oxygen atoms

Therefore, the number of oxygen atoms are, $37.94\times 10^{23}$