For this case we must find a linear equation of the form:
[tex] v = mt + b [/tex]
Where,
b: initial value of the car
m: decrease rate per year
t: number of years
v: value of the car
For the slope of the line we have:
[tex] m = \frac{v2-v1}{t2-t1} [/tex]
[tex] m = \frac{18823-23500}{3-0} [/tex]
[tex] m = \frac{-4677}{3} [/tex]
[tex] m = -1559 [/tex]
The initial value of the car is:
[tex] b = 23500 [/tex]
So, replacing values we have:
[tex] v = -1559t + 23500 [/tex]
Answer:
a formula which expresses its value, v, in terms of its age, t, in years is:
[tex] v = -1559t + 23500 [/tex]