1.5 min = 90 sec
(25 m/s²) x (90 sec) =
(25 x 90) (m - s / s²) = 2,250 m/s .
At the end of 1.5 min of acceleration, the object will be moving 2,250 m/s faster than it was at the beginning of the 1.5 min.
We don't know how fast that is, because you never told us how fast it was moving when the acceleration started.
(I'd stand out of the way of that object if I were you. 2,250 m/s is a little over 5,000 miles per hour ! And that's on top of whatever speed it had before it started accelerating ... at better than 2.5 G's !)
The question is incomplete, here is the complete question:
If an object is accelerating at a rate of 25 m/s² how fast will it be moving in 1.50 min
? (Assume that the initial velocity is zero)
Answer: The object is moving with the velocity of 2250 m/s
Explanation:
To calculate the speed of the object, we use first equation of motion:
[tex]v=u+at[/tex]
where,
v = final velocity of the object = ? m/s
u = initial velocity of the object = 0 m/s
a = acceleration of the object = [tex]25m/s^2[/tex]
t = time taken = 1.50 min = 90 seconds (Conversion factor: 1 min = 60 seconds)
Putting values in above equation, we get:
[tex]v=0+(25\times 90)\\\\v=2250m/s[/tex]
Hence, the object is moving with the velocity of 2250 m/s
