Question

A bus leaves an intersection accelerating at 2.0m/s^2. where is the bus after 5.0s

Answer 1

Assuming the bus starts from rest, the position of the bus after a time t will be given by

$S=\frac{1}{2}at^2$

where

a=2.0 m/s^2 is the acceleration of the bus

t=5.0 s is the time

Substituting into the equation, we find

$S=\frac{1}{2}at^2=\frac{1}{2}(2.0 m/s^2)(5.0 s)^2=25 m$