Question

PQ=2x-3. if QR=5x+7 and PR=10x-11, then PR=?

Answer 1

Given: PQ=2x-3. if QR=5x+7 and PR=10x-11

To Find: PR

Solution: From the attached diagram, point P, Q and R are co-linear.

Hence,       PR = PQ + QR

or,         10x-11 = 2x-3 + 5x+7

or,      10x - 7x = 15

or,                 x = 5

Now, we shall calculate the value of PR

                 PR = 10x-11

or,              PR = 10× 5 - 11

or,              PR = 39

Hence, the required value of PR will be 39.