Cajell Cajell
  • 29-08-2018
  • Mathematics
contestada

How to solve?

k-3k=6k+5(-3a+1)

Respuesta :

gmany
gmany gmany
  • 30-08-2018

[tex] \text{Solve for k}\\\\k-3k=6k+5(-3a+1)\ \ \ \ |\text{use distributive property}\\\\-2k=6k+5(-3a)+5(1)\ \ \ \ \ |-6k\\\\-8k=-15a+5\ \ \ \ \ |:(-8)\\\\\boxed{k=\dfrac{15a-5}{8}}\\\\\text{Solve for a}\\\\6k+5(-3a+1)=k-3k\ \ \ \ |\text{use distributive property}\\\\6k-15a+5=-2k\ \ \ \ \ |-6k\\\\-15a+5=-8k\ \ \ \ |-5\\\\-15a=-8k-5\ \ \ \ \ |:(-15)\\\\\boxed{a=\dfrac{8k+5}{15}} [/tex]

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