Question

(07.02) How many solutions can be found for the equation 3y + 5 − 2y = 11? Zero One Two Infinitely many

Answer 1

Solve for y:

3 y - 2 y + 5 = 11

Grouping like terms, 3 y - 2 y + 5 = (3 y - 2 y) + 5:

(3 y - 2 y) + 5 = 11

3 y - 2 y = y:

y + 5 = 11

Subtract 5 from both sides:

y + (5 - 5) = 11 - 5

5 - 5 = 0:

y = 11 - 5

11 - 5 = 6:

Answer: | y = 6 ; thus 1 Answer

Answer 2

only 1 way to solve it