Here are a few rules you need to know for this equation:
So this is our algebraic expression: [tex] \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}} [/tex]
Firstly, multiply 3^-4 and 3^2: [tex] \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}} [/tex]
Next, divide:
[tex] \frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1} [/tex]
Next, turn the negative exponent into a positive one: [tex] 3^12^{-1}= \frac{3}{2} [/tex]
Your final answer is 3/2, or 1.5.