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A town's population is 43,425 about 125 move out of the town each month 200 people on average move into town a nearby town has a population of 45k it has no one moving in and an average of 150 ppl moving away every month in about how many months will the population of the town's be equal write an equation that represents the situation and solve

Respuesta :

Let us suppose after x months the population of both town's will be equal.

From the given directions, we have

The population of the first town after x months is given by

[tex]200x-125x+43425[/tex]

The population of the second town after x months is  given by

[tex]45000-150x[/tex]

In order to the population of the both town's to be equal, we have

[tex]200x-125x+43425= 45000-150x[/tex]

This is the required equation that represents the given situation.

Now, let us solve the equation

[tex]200x-125x+43425=\:45000-150x\\ \mathrm{Add\:similar\:elements:}\:200x-125x=75x\\ 5x+43425=45000-150x\\ \mathrm{Subtract\:}43425\mathrm{\:from\:both\:sides}\\ 75x=-150x+1575\\ \mathrm{Add\:}150x\mathrm{\:to\:both\:sides}\\ 225x=1575\\ \mathrm{Divide\:both\:sides\:by\:}225\\ x=7[/tex]

Therefore, after 7 months the population of both town's will be equal.

Answer:

Step-by-step explanation:

75x+43425=4500=-150x

how is this x=7?

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