Question

An empty flask has a mass of 123.4 g. When the flask is filled with water, the madd is 211.6g. If 10.0g of zinc (d=7.14 g/cm^3) are added to the flask filled with water (and the sides of the flask are dried from the displaced water) what is the new volume in the flask? (Hint: you are going to have to use the density of water to answer this question)

Answer 1

Answer:- 89.6 mL

Solution:- Mass of empty flask = 123.4 g

mass of flask filled with water = 211.6 g

So, mass of water in the flask = 211.6 g - 123.4 g = 88.2 g

we know that density of water is $1.00\frac{g}{mL}$ .

$volume=\frac{mass}{density}$

So, volume of water in the flask = $88.2g(\frac{1mL}{1g})$

= 88.2 mL

Mass and density is also given for Zn metal. So, we could calculate the volume of metal also using the same formula used for water.

volume of Zn = $10.0g(\frac{1cm^3}{7.14g})(\frac{1mL}{1cm^3})$

= 1.40 mL

New volume of the flask would be the sum of the volumes of water and metal.

So, new volume of the flask = 88.2 mL + 1.40 mL = 89.6 mL

Hence, the new volume of the flask after adding the metal to it is 89.6 mL.