A person's heartbeat is 71 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does the person live? Disregard leap years.

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First step: identify how many heart beats in a year.

To determine the heart beats in a year multiply the heart  beats in a minute with [tex](60\times 24\times 365)[/tex] years.  

Thus, heart beats in a year comes out to be = [tex]71 \times (60\times 24\times 365) years[/tex]

= [tex]37317600[/tex] heart beats in a year

Heart beats [tex]3.1\times 10^{9}[/tex] in a life time.

Thus, number of years he lives is calculated by the division of  heart beats in a year and heart beats in a life time.

Number of years he lives = [tex]\frac{3.1\times 10^{9}}{37317600}[/tex]

= [tex]8.3\times 10^{-8}\times 10^{9}[/tex]

= [tex]8.3\times 10[/tex]

= [tex]83.0 [/tex] years

Thus, number of years he lives is [tex]83.0 [/tex] years

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