Equation 1: x² + y = 7
Equation 2: 3x + 7 = 9
Use Equation 2 to solve for "x" and plug in "x" into Equation 1 to solve for "y".
3x + 7 = 9
3x = 2
x = [tex] \frac{2}{3} [/tex]
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x² + y = 7
([tex] \frac{2}{3} [/tex])² + y = 7
[tex] \frac{4}{9} [/tex] + y = 7
y = 7 - [tex] \frac{4}{9} [/tex]
y = [tex] \frac{63}{9} [/tex] - [tex] \frac{4}{9} [/tex]
y = [tex] \frac{59}{9} [/tex]
Answer: ([tex] \frac{2}{3} [/tex], [tex] \frac{59}{9} [/tex])
