Question

the length of a rectangle is one more than four times its width. if the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle

Answer 1

Length (L): 4w + 1

width (w): w

Perimeter (P) = 2L + 2w

62 = 2(4w + 1) + 2(w)

62 = 8w + 2 + 2w

62 = 10w + 2

60 = 10w

6 = w

Length: L = 4w + 1 → 4(6) + 1 → 24 + 1 → 25

Answer: 6 x 25

Answer 2

Answer:

Length of the rectangle = 25 m

width of the rectangle = 6 m

Step-by-step explanation:

Let x be the length of the rectangle and w be the width

the length of a rectangle is one more than four times its width

$l=4w+1$

Perimeter of rectangle = 2 times length + 2 times width

$Perimeter = 2(l) +2(w)$

$62=2(4w+1)+2w$

$62=8w+2+2w$

$62=10w+2$

Subtract 2 from both sides

$60=10w$

Divide by 10 on both sides

$6=w$

So width of the rectangle = 6 m

Length is $l=4w+1$

$l=4(6)+1=25$

Length of the rectangle = 25 m