What is the mass of 6.02 x 10^23 atoms of potassium

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29-08-2018
Chemistry

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What is the mass of 6.02 x 10^23 atoms of potassium

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midknight9 midknight9 · Answer 1 · 2018-08-29T04:42:10+02:00

So we know that this amount of atoms is Avogadro's number - the number of atoms in 1 mole of a substance.

So then, using dimensional analysis, we can find the mass, in grams, of potassium.

First we must find the molar weight of potassium as found on the periodic table: 39.098g/mol

Then we can solve directly for mass:

[tex] \frac{6.022x10^{23}atoms}{1}*\frac{1mol}{6.022x10^{23}atoms}*\frac{39.098g}{1mol}=39.098g [/tex]

Therefore, the amount of atoms you have given, in terms of mass, will equal 39.098g - if the answer requires significant figures, then the mass would be 39.1g of potassium.