how do you solve step by step?

[tex] \bf 3y=\cfrac{8-12y}{4}+2\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{12y=8-12y+8}
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12y=-12y+16\implies 24y=16\implies y=\cfrac{16}{24}\implies y=\cfrac{2}{3} [/tex]
if you wonder why we multiplied by the LCD of 4, is just to do away with the denominators.
Firstly, subtract 2 on both sides of the equation: [tex] 3y-2=\frac{8-12y}{4} [/tex]
Next, multiply both sides by 4: [tex] 12y-8=8-12y [/tex]
Next, add both sides by 12y: [tex] 24y-8=8 [/tex]
Next, add both sides by 8: [tex] 24y=16 [/tex]
Lastly, divide both sides by 24 and your answer will be [tex] y=\frac{16}{24}=\frac{2}{3} [/tex]