Find the constant rate of change for each table

the constant rate of change, or average rate of change, is just its slope, so we can just pick any two points to get it.
[tex] \bf \begin{array}{|cc|ll}\cline{1-2}\stackrel{x}{time}&\stackrel{y}{distance}\\\cline{1-2}1&6\\\underline{2}&\underline{12}\\3&18\\\underline{4}&\underline{24}\\\cline{1-2}\end{array}~\hspace{7em}\begin{array}{llll}(\stackrel{x_1}{2}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{24})\\\\\\slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{24-12}{4-2}\\\\\\\cfrac{12}{2}\implies 6\end{array} [/tex]
The constant rate of change for the table is 6m per 1s.
The constant rate of change exists in linear mathematical relationships and is simply given as the slope.
In this scenario, the rate of change is given as;
Ultimately, the constant rate of change is;
Rate of change = 6m per 1s.
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