Question

henry is one more than two times as old as Enrique . in 14 years, the sum of their ages will be 62. How old is Enrique?

Answer 1

Let x = age of Enrique

• Enrique in 14 years = x + 14
• Henry in 14 years = 2x + 1 +14
• Sum in 14 years = 62

Using this info, our equation is $x+14+2x+1+14=62$ . From here we can solve for x:

$x+14+2x+1+14=62 \\3x+29=62\\3x=33\\x=11$

Enrique is 11 years old.

Answer 2

The age of Enrique is 11 years.

SOLUTION:

Given that, Henry is one more than two times as old as Enrique.  

In 14 years, the sum of their ages will be 62.  

We have to find the age of Enrique. Now, let the age of Enrique be n years.

Then, age of Henry becomes $1+2 \times n \rightarrow 2 n+1$

And, in 14 years their ages becomes n + 14 and 2n + 1 + 14 = 2n + 15 respectively.

We know that their sum of ages = 62  

$\Rightarrow n+14+2 n+15=62 \rightarrow 3 n+29=62 \rightarrow \rightarrow 3 n=62-29 \rightarrow 3 n=33 \rightarrow n=11$