ericklsx ericklsx
  • 28-08-2018
  • Mathematics
contestada

What is the vertex of the quadratic function below y=2x^2 - 4x+1

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tramserran
tramserran tramserran
  • 28-08-2018

Identify the "a, b, c" values, find the axis of symmetry (AOS), and plug in the x-coordinate to find the y-coordinate.

a, b, c: y = ax² + bx + c → a = 2, b = -4, c = 1

AOS: x = [tex] \frac{-b}{2a} [/tex] = [tex] \frac{-(-4)}{2(2)} [/tex] = [tex] \frac{4}{4} [/tex] = 1

y-coordinate: y = 2x² - 4x + 1 = 2(1)² - 4(1) + 1 = 2 - 4 + 1 = -1

Answer: (1, -1)


Answer Link
brain2008 brain2008
  • 13-07-2022

Answer: (1,-1)

Step-by-step explanation: Indeed person in the top is right.

Answer Link

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