we are given that
8 more than a number is greater than or equal to 0
Let's assume that number as 'x'
8 more than a number is
[tex]x+8[/tex]
now, it is greater than or equal to 0
so, we can write as
[tex]x+8\geq 0[/tex]
now, we can solve for x
Subtract both sides 8
[tex]x+8-8\geq 0-8 [/tex]
[tex]x\geq -8 [/tex]...............Answer