Question

Which equation describes this line (-3,2)(1,10)

Answer 1

The answer is D because if you make the equation into the form y=mx + b, b is the y intercept. B must equal 8 because thats the intercept, and that is the only equation where the constant equals 8 when put on the right side. If this is right could you possibly give me brainliest? Hope this helped.

Answer 2

You can use the formula for finding the equation of straight line which passes through two given points.

The equation of the given line is given by:

Option D: $y-10 = 2(x - 1)$

How to find the equation of line which passes through two given points?

Lets suppose that there are two points $(x_1, y_1)$  and  $(x_2,y_2)$  on the Cartesian coordinate plane.

Then the equation of the straight line passing through these two points is given by:

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1)$

Using above formula to find the equation of needed line

Since the given line passes through (-3,2) and (1,10), thus,

$x_1 = -3, y_1 = 2\\x_2 = 1, y_2 = 10$

Putting these values in the aforesaid equation of straight line passing through  $(x_1, y_1)$  and  $(x_2,y_2)$ :

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1)\\y\\ y- 2 = \dfrac{10 - 2}{1 - (-3)} (x - (-3))\\\\y-2 = \dfrac{8}{4}(x+3)\\\\y-2 = 2(x+3)\\\\y = 2x + 6 +2\\\\y = 2x + 8$

Thus, the equation of needed line is given by $y= 2x + 8$

The aforesaid equation can be rewritten as:

$y = 2x + 8\\y - 10 = 2x + 8 - 10\\y - 10 = 2x - 2\\y - 10 = 2(x-1)$ (subtracted 10 from both sides)

Thus, Option D: $y-10 = 2(x - 1)$ is correct here.

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