[tex] y=\dfrac{x}{x^2+1}\\\\-y=-\dfrac{-x}{(-x)^2+1}\\-y=\dfrac{x}{x^2+1}\\y=-\dfrac{x}{x^2+1} [/tex]
[tex] -\dfrac{x}{x^2+1}\not =\dfrac{x}{x^2+1} [/tex] so it's not symmetrical about the origin.